If it's not what You are looking for type in the equation solver your own equation and let us solve it.
(5x^2)-20x=65
We move all terms to the left:
(5x^2)-20x-(65)=0
a = 5; b = -20; c = -65;
Δ = b2-4ac
Δ = -202-4·5·(-65)
Δ = 1700
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$
The end solution:
$\sqrt{\Delta}=\sqrt{1700}=\sqrt{100*17}=\sqrt{100}*\sqrt{17}=10\sqrt{17}$$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-20)-10\sqrt{17}}{2*5}=\frac{20-10\sqrt{17}}{10} $$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-20)+10\sqrt{17}}{2*5}=\frac{20+10\sqrt{17}}{10} $
| 10a-2(3a-4)=30 | | (x+17)(3)=5 | | (x+12)=(4x-45) | | 10+8=-2x | | 62=x/15 | | 400+67x=400+87x | | -2x+3(3x-4)=30 | | 3(5x+3)=15x+B | | 108=y+72 | | Y=7/5x+11 | | {x+17}{3}=5 | | –9r+8=–10r | | 2=n+1/5= | | 5(2g-3)=45 | | -2(3x-1)=5x+28+2x | | -8-3p-2=7 | | 9j-6=-60 | | 3(5x+3)=15x+7 | | -2x-7(1x+3)=111 | | 80+5x+30=140 | | 19n-8=144 | | 2h+7-6h=31 | | x2(x-5)=5x+23 | | 3x+4(x+1)=7x+4 | | 20+4*r=32-2*r | | -29-8m=-8(1+6m)-3 | | 20+4n=2(n+2) | | 11-+4d=71 | | -12=13x-9x* | | -3x-4+1=15 | | 3h-2(5+4h)=-5h-10 | | n-21=17 |